Chapter 1: Getting started with algorithms
Section 1.1: A sample algorithmic problemAn algorithmic problem is specified by describing the complete set of instances it must work on and of its output
after running on one of these instances. This distinction, between a problem and an instance of a problem, is
fundamental. The algorithmic problem known as sorting is defined as follows: [Skiena:2008:ADM:1410219]
Problem: Sorting
Input: A sequence of n keys, a_1, a_2, ..., a_n.
Output: The reordering of the input sequence such that a'_1 <= a'_2 <= ... <= a'_{n-1} <= a'_nAn instance of sorting might be an array of strings, such as { Haskell, Emacs } or a sequence of numbers such as{ 154, 245, 1337 }.Section 1.2: Getting Started with Simple Fizz Buzz Algorithm in
SwiftFor those of you that are new to programming in Swift and those of you coming from different programming bases,
such as Python or Java, this article should be quite helpful. In this post, we will discuss a simple solution for
implementing swift algorithms.Fizz BuzzYou may have seen Fizz Buzz written as Fizz Buzz, FizzBuzz, or Fizz-Buzz; they're all referring to the same thing. That
"thing" is the main topic of discussion today. First, what is FizzBuzz?
This is a common question that comes up in job interviews.
Imagine a series of a number from 1 to 10.1 2 3 4 5 6 7 8 9 10Fizz and Buzz refer to any number that's a multiple of 3 and 5 respectively. In other words, if a number is divisible
by 3, it is substituted with fizz; if a number is divisible by 5, it is substituted with buzz. If a number is simultaneously
a multiple of 3 AND 5, the number is replaced with "fizz buzz." In essence, it emulates the famous children game
"fizz buzz".
To work on this problem, open up Xcode to create a new playground and initialize an array like below:// for examplelet number = [1,2,3,4,5]// here 3 is fizz and 5 is buzzTo find all the fizz and buzz, we must iterate through the array and check which numbers are fizz and which are
buzz. To do this, create a for loop to iterate through the array we have initialised:for num in number {// Body and calculation goes here}After this, we can simply use the "if else" condition and module operator in swift ie - % to locate the fizz and buzz
after running on one of these instances. This distinction, between a problem and an instance of a problem, is
fundamental. The algorithmic problem known as sorting is defined as follows: [Skiena:2008:ADM:1410219]
Problem: Sorting
Input: A sequence of n keys, a_1, a_2, ..., a_n.
Output: The reordering of the input sequence such that a'_1 <= a'_2 <= ... <= a'_{n-1} <= a'_nAn instance of sorting might be an array of strings, such as { Haskell, Emacs } or a sequence of numbers such as{ 154, 245, 1337 }.Section 1.2: Getting Started with Simple Fizz Buzz Algorithm in
SwiftFor those of you that are new to programming in Swift and those of you coming from different programming bases,
such as Python or Java, this article should be quite helpful. In this post, we will discuss a simple solution for
implementing swift algorithms.Fizz BuzzYou may have seen Fizz Buzz written as Fizz Buzz, FizzBuzz, or Fizz-Buzz; they're all referring to the same thing. That
"thing" is the main topic of discussion today. First, what is FizzBuzz?
This is a common question that comes up in job interviews.
Imagine a series of a number from 1 to 10.1 2 3 4 5 6 7 8 9 10Fizz and Buzz refer to any number that's a multiple of 3 and 5 respectively. In other words, if a number is divisible
by 3, it is substituted with fizz; if a number is divisible by 5, it is substituted with buzz. If a number is simultaneously
a multiple of 3 AND 5, the number is replaced with "fizz buzz." In essence, it emulates the famous children game
"fizz buzz".
To work on this problem, open up Xcode to create a new playground and initialize an array like below:// for examplelet number = [1,2,3,4,5]// here 3 is fizz and 5 is buzzTo find all the fizz and buzz, we must iterate through the array and check which numbers are fizz and which are
buzz. To do this, create a for loop to iterate through the array we have initialised:for num in number {// Body and calculation goes here}After this, we can simply use the "if else" condition and module operator in swift ie - % to locate the fizz and buzz
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